Statistics Assignment
StatisticsAssignment
StatisticsAssignment
QuestionOne

Tree diagram (0.46) A
(0.88)L
A (0.54)
Sending (0.11) (0.12)L’
Troops (0.42) L
(0.89) D
(0.47) L’
A=Probabilityof Approval
D=Probability of Disapproval (Not Approve)
L=Probability of Liberal Party Voter
L’=Probability of not a Liberal Party Voter
b)Probability that the person is a Liberal party voter
88/100=0.88
c)The probability that the person is not a Liberal party voter andapproves the decision to send an extra 500 troops to Iraq
Probabilitythat is not a liberal party voter (L’) = 12/100= 0.12
Probabilityof Approving (A) = 11/100= 0.11
Probability=0.11*.012= 0.0132
d)If the person selected approves the decision to send an extra 500troops to Iraq, what is the probability the person is a Liberal partyvoter?
Probabilityof Approving (A) = 11/100= 0.11
Probabilitythat is a liberal party voter (L) = 88/100= 0.88
Probability(AL) = 0.0968
e)What is the probability that the person is not a Liberal party voteror disapproves the decision to send an extra 500 troops to Iraq
Probabilitynot a liberal party voter (L’) = 0.12
Probabilitythat disapproves the decision= 0.89
QuestionTwo
First,there is identification of the hypotheses, null and alternativehypotheses (Killeen, 2005). H0 (Null Hypothesis) = the mean amount oftelevision watched daily by all young adult men is greater than Vminutes
H1(Alternative Hypothesis) = the mean amount of television watcheddaily by all young adult men is not greater than V minutes
Significancelevel (a)= 0.05
IV
No.of Observations= 5
Mean=130/5= 26
s.d=10
variance=100
V
456/15=30.4
s.d=10
Variance=100
Caculating,the null hypothesis is significant thus we fail to reject it.
References
Killeen,P. R. (2005). An alternative to nullhypothesis significancetests.Psychologicalscience, 16(5),345353.