Statistics Assignment

# Statistics Assignment

StatisticsAssignment

StatisticsAssignment

QuestionOne

1. Tree diagram (0.46) A

(0.88)L

A (0.54)

Sending (0.11) (0.12)L’

Troops (0.42) L

(0.89) D

(0.47) L’

A=Probabilityof Approval

D=Probability of Disapproval (Not Approve)

L=Probability of Liberal Party Voter

L’=Probability of not a Liberal Party Voter

b)Probability that the person is a Liberal party voter

88/100=0.88

c)The probability that the person is not a Liberal party voter andapproves the decision to send an extra 500 troops to Iraq

Probabilitythat is not a liberal party voter (L’) = 12/100= 0.12

Probabilityof Approving (A) = 11/100= 0.11

Probability=0.11*.012= 0.0132

d)If the person selected approves the decision to send an extra 500troops to Iraq, what is the probability the person is a Liberal partyvoter?

Probabilityof Approving (A) = 11/100= 0.11

Probabilitythat is a liberal party voter (L) = 88/100= 0.88

Probability(AL) = 0.0968

e)What is the probability that the person is not a Liberal party voteror disapproves the decision to send an extra 500 troops to Iraq

Probabilitynot a liberal party voter (L’) = 0.12

Probabilitythat disapproves the decision= 0.89

QuestionTwo

First,there is identification of the hypotheses, null and alternativehypotheses (Killeen, 2005). H0 (Null Hypothesis) = the mean amount oftelevision watched daily by all young adult men is greater than Vminutes

H1(Alternative Hypothesis) = the mean amount of television watcheddaily by all young adult men is not greater than V minutes

Significancelevel (a)= 0.05

IV

No.of Observations= 5

Mean=130/5= 26

s.d=10

variance=100

V

456/15=30.4

s.d=10

Variance=100

Caculating,the null hypothesis is significant thus we fail to reject it.

References

Killeen,P. R. (2005). An alternative to null-hypothesis significancetests.Psychologicalscience,&nbsp16(5),345-353.